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April 10, 2010

Note on using .style.display on <TR id=… >

by Joe Kuan

I always thought .style.display property only have two values, ‘block’ and ‘none’, until I came across a problem on displaying and hiding a table row.

I have the following HTML script:

<TABLE class=... >
<TR>
  <TD>Type:</TD>
  <TD><SELECT name=row_option onchange="javascript:display_row();">
   ...
  </SELECT></TD>
</TR>
<TR id="eni"><TD>Drop:</TD><TD>...</TD></TR>
<TR id="meeni"><TD>Custom:</TD><TD>...</TD></TR>
</TABLE>

What the above script does is basically when an option is selected, the ‘eni’ table row is displayed and ‘meeni’ row is hidden, vice versa when another option is selected.

The Javascript function (with Prototype) for setting the display:

function display_row(form_element) {
   if (form_element.row_option.selectedIndex == 0) {
     $('eni').style.display = 'block';
     $('meeni').style.display = 'none';
   } else {
     $('eni').style.display = 'none';
     $('meeni').style.display = 'block';
   }
}

However, the problem is that the display of the table form mysteriously not aligned properly. Following is the screenshot:

After a while, looking up the HTML DOM reference, I never realised there is actually a number of values for style.display property. As soon as I replaced the keyword ‘block’ to ‘table-row’. The form is displayed as expected. Silly me.

I work for iTrinegy. Here are my other Javascript

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